Los Angeles (AFP) - Australian star Andrew Bogut has inked a one-year deal with the Los Angeles Lakers, the player's agent said on Tuesday.

Bogut, 32, has been a free agent since parting with the Cleveland Cavaliers in March, when he sustained a broken leg on his debut for the club.

The deal, which was confirmed by his agent David Bauman on Twitter, is reportedly worth US$2.3 million (S$3 million) for the towering centre.

Bogut endured a nomadic 2016-2017 season, starting out with the Dallas Mavericks where he averaged three points and 8.4 rebounds in 26 games.

He was later traded to the Philadelphia 76ers and then reached a buyout agreement in February which freed him to join the Cavaliers.

However his Cleveland career lasted just 58 seconds after a collision with Miami's Okaro White left him with a fractured tibia.

Bogut, the No. 1 pick in the 2005 draft, was a member of the Golden State Warriors team which won the NBA Finals in 2015 and were runners-up the following season.

Bogut's best season in a 13-year NBA (National Basketball Association) career came in 2009-2010, when he averaged 15.2 points and 10.2 rebounds for the Milwaukee Bucks.